601. Human Traffic of Stadium
Question:

Solution:
select
s.id,
s.visit_date,
s.people
from stadium s
join (
select
grp,
min(visit_date) as min_date,
max(visit_date) as max_date,
datediff(max(visit_date), min(visit_date)) as diff
from(
select
id,
visit_date,
people,
row_number() over(order by visit_date) as r,
id - (row_number() over(order by visit_date)) as grp
from stadium
where people >= 100
) s
group by 1
having datediff(max(visit_date), min(visit_date)) >= 2
) m
on s.visit_date >= m.min_date
and s.visit_date <= m.max_date
order by 2
602. Friend Requests II: Who Has the Most Friends
Question:

Solution:
select
fid as id,
num
from (
select
fid,
sum(freq) as num
from(
select
requester_id as fid,
1 as freq
from request_accepted
union all
select
accepter_id as fid,
1 as fred
from request_accepted
) f
group by 1
) a
order by num desc
limit 1
603. Consecutive Available Seats
Question:

Solution:
select
seat_id
from(
select
seat_id,
free,
lead(free,1) over(order by seat_id) as lead_free,
lag(free,1) over(order by seat_id) as lag_free
from cinema
) c
where free <> 0
and (
lead_free = free
or lag_free = free
)